使用正则表达式从字符串中提取数字 [英] Extracting numbers from a string using regular expressions

问题描述

我对正则表达式一无所知，但我知道它们是我在这里尝试执行的操作的正确工具:我正在尝试从这样的字符串中提取数值:

I am clueless about regular expressions, but I know that they're the right tool for what I'm trying to do here: I'm trying to extract a numerical value from a string like this one:

approval=not requested^assignment_group=12345678901234567890123456789012^category=Test^contact_type=phone^

理想情况下，我会从中提取以下内容:12345678901234567890123456789012 我尝试过的所有正则表达式都不起作用.我怎样才能从这个字符串中得到我想要的值?

Ideally, I'd extract the following from it: 12345678901234567890123456789012 None of the regexes I've tried have worked. How can I get the value I want from this string?

推荐答案

mystr.match(/assignment_group=([^\^]+)/)[1]; //=> "12345678901234567890123456789012"

这将找到从assignment_group="结尾到下一个脱字符^ 符号的所有内容.

This will find everything from the end of "assignment_group=" up to the next caret ^ symbol.

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