为什么这个正则表达式不起作用? [英] Why isnt this regex working?

问题描述

我正在尝试为类似于以下地址的地址设置正则表达式模式，但我无法让测试方法返回 true，我在这里做错了什么?

I'm trying to have a regex pattern for an address similar to the one below but I cant get the test method to return true, what am I doing wrong here?

       let reg=/[0-9]{3}\b[a-z]{1}\b\d{2}[a-z]{2}\b[a-z]{2}\b[a-z}{6}\b[a-z]{10}\b[0-9]{5}/;

       let fakeAddress="925 s 10th st tacoma washington 98405";
        reg.test(fakeAddress);

推荐答案

没有单词边界 字母和数字之间以及数字和字母之间，您想匹配它们之间的空格.请记住，\b，一个字边界，是一个不消耗任何字符的零宽度断言.因此，您需要将所有 \b 替换为 \s+ (1 个或多个空白字符).另外， [a-z} 是一个错字.应该是 [a-z].

There are no word boundaries between letters and digits and between digits and letters, you wanted to match whitespace between them. Remember that \b, a word boundary, is a zero-width assertion that does not consume any chars. So, you need to replace all \b with \s+ (1 or more whitespace chars). Also, [a-z} is a typo. it should be [a-z].

使用

/\d{3}\s+[a-z]\s+\d{2}[a-z]{2}\s+[a-z]{2}\s+[a-z]{6}\s+[a-z]{10}\s+[0-9]{5}/

查看正则表达式演示

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