用于删除字符串末尾字符的正则表达式 [英] regex for removing characters at end of string

问题描述

我想递归匹配所有以 : 或 / 或 ; 或 , 结尾的文本并删除所有这些字符，以及文本末尾留下的任何空格.

i would like to match recursively, all text that ends with : or / or ; or , and remove all these characters, along with any spaces left behind, in the end of the text.

示例:

some text :  ;  ,    / 

应该变成:

some text

我尝试过的只是删除找到的任何这些特殊字符的第一次出现，如何递归地执行此操作，以便删除所有字符找到那场比赛了吗?我使用的正则表达式:

What i have tried, just removes the first occurrence of any of these special characters found, how one can do this recursively, so as to delete all characters found that match? regex i use:

查找:[ ,;:/]*

什么都没有替换

推荐答案

[ ,;:/]*$ 应该是你所需要的.这与您当前的正则表达式相同，只是末尾带有 $.$ 告诉它匹配必须发生在字符串的末尾.

[ ,;:/]*$ should be what you need. This is the same as your current regex except with the $ on the end. The $ tells it that the match must happen at the end of the string.

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