Python将反斜杠转换为正斜杠 [英] Python Convert Back Slashes to forward slashes

问题描述

我在 python 中工作，我需要转换这个:

I am working in python and I need to convert this:

C:\folderA\folderB 到 C:/folderA/folderB

C:\folderA\folderB to C:/folderA/folderB

我有三种方法:

dir = s.replace('\\','/')

dir = os.path.normpath(s) 

dir = os.path.normcase(s)

在每个场景中的输出都是

In each scenario the output has been

C:folderAfolderB

C:folderAfolderB

我不确定我做错了什么，有什么建议吗?

I'm not sure what I am doing wrong, any suggestions?

推荐答案

您的具体问题是 replace 参数的顺序和转义，应该是

Your specific problem is the order and escaping of your replace arguments, should be

s.replace('\\', '/')

然后是:

posixpath.join(*s.split('\\'))

在 *nix 平台上相当于:

Which on a *nix platform is equivalent to:

os.path.join(*s.split('\\'))

但是不要在 Windows 上依赖它，因为它更喜欢特定于平台的分隔符.还有:

But don't rely on that on Windows because it will prefer the platform-specific separator. Also:

请注意，在 Windows 上，因为每个目录都有一个当前目录drive, os.path.join("c:", "foo") 表示相对于驱动器 C: (c:foo) 上的当前目录，而不是 c:\foo.

Note that on Windows, since there is a current directory for each drive, os.path.join("c:", "foo") represents a path relative to the current directory on drive C: (c:foo), not c:\foo.

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