如何在特定字符之前替换字符串的子字符串? [英] How do I replace a substring of a string before a specific character?

问题描述

表格电子邮件:

值:

[e-mail]
[e-mail]
[e-mail]

我想用 test 替换 @ 之前的字符串.

I want to replace the string before @ with test.

结果:

[e-mail]
[e-mail]
[e-mail]

如何使用子串并根据字符串中的字符进行替换?

How do I use substringing and replace based on a character in the string?

推荐答案

你甚至不需要使用substring或replace，你可以使用这个:>

You don't even need to use substring or replace, you can use this:

SELECT 'test' + RIGHT(email, charindex('@', REVERSE(email)))
FROM YourTable

你可以用这个来测试一下:

You can test it out with this:

DECLARE @email nvarchar(50)
SET @email = '[e-mail]'
PRINT 'test' + RIGHT(@email, charindex('@', REVERSE(@email)))

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