Javascript 替换左括号和右括号 [英] Javascript replace opening and closing brackets

问题描述

我有一个文本字符串，例如

I have a string of text, for example

[text1] [text2] [text3]

我想用${"替换["字符，用}"替换]"字符，但仅在这种情况下，当["后跟]"时.

I want to replace "[" character with "${" and "]" character with "}", but only in that case, when "[" is followed up by "]".

例如

[text1] [[text2] [text3]

应该导致

${text1} [${text2} ${text3}

如何使用 Javascript 中的正则表达式来实现?

How can I accomplish that with regex in Javascript?

我是这样写的

someString = someString.replace(/\[/g, "${");
someString = someString.replace(/]/g, "}");

但这对我的问题不起作用，它只是替换了每个括号.

But it doesn't work for my problem, it just replaces every bracket.

推荐答案

您可以使用

var s = "[text1] [[text2] [text3]";
console.log(s.replace(/\[([^\][]+)]/g, "$${$1}"));

详情

• \[ - 一个 [ 字符
• ([^\][]+) - 第 1 组:a 否定字符类匹配除 [ 和 ] 之外的任何 1+ 字符(注意，在 JS 正则表达式中的字符类中，] char 必须始终被转义，即使它被放置在否定类的开头)
• ] - 一个 ] 字符(在字符类之外，] 并不特殊，不需要转义).

• \[ - a [ char
• ([^\][]+) - Group 1: a negated character class matching any 1+ chrs other than [ and ] (note that inside a character class in a JS regex, the ] char must always be escaped, even if it is placed at the negated class start)
• ] - a ] char (outside of a character class, ] is not special and does not have to be escaped).

在替换模式中，$$ 代表文字 $ 字符，{ 添加一个 { 字符, $1 插入 Group 1 值，然后添加 }.

In the replacement pattern, $$ stands for a literal $ char, { adds a { char, $1 inserts the Group 1 value and then a } is added.

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