为什么即使我的 Perl 就地脚本失败了，它也会以零退出代码退出? [英] Why is my Perl in-place script exiting with a zero exit code even though it's failing?

问题描述

我有一个单行 Perl 搜索和替换，大致如下所示:

I have a one-liner Perl search and replace that looks roughly like this:

perl -p -i -e 's/foo/bar/' non-existent-file.txt

因为文件不存在(这不是故意的，但这是自动构建脚本的一部分，所以我想防止出现这种情况)，Perl 退出并出现此错误:

Because the file doesn't exist (which isn't intentional, but this is part of an automated build script, so I want to protect against that), Perl exits with this error:

Can't open non-existent-file.txt: No such file or directory.

然而，退出代码仍然为零:

However, the exit code is still zero:

echo $?
0

我做错了吗?我应该修改我的脚本，还是我调用 Perl 的方式?我天真地假设因为 Perl 找不到该文件，它会以非零代码退出.

Am I doing something wrong? Should I be modifying my script, or the way I'm invoking Perl? I was naively assuming that because Perl couldn't find the file, it would exit with a non-zero code.

推荐答案

你可以通过死亡来强制错误，

You can force error by dying,

perl -p -i -e 'BEGIN{ -f $ARGV[0] or die"no file" } s/foo/bar/' non-existent-file.txt

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