搜索时如何仅使用星号通配符? [英] How to use just asterisk wildcard when searching?

问题描述

我只想支持星号(*)通配符而不是正则表达式.

I want to just support asterisk(*) wildcard not regex.

这是我的代码:

for example : checkNames[i] = "Number of ongoing MS sessions"


var checkName = checkNames[i].split("*").join(".*");
supportRegExp(dataSource[j].ColumnName, checkName, validatedList,dataSource[j]);

这是我的 supportRegExp 函数:

and this is my supportRegExp function :

function supportRegExp(arrayElem, checkName, validatedList, elem) {
    var regexpArr = checkName
        .replace(/\t/g, '\n')
        .split("\n")
        .map(function (item) { 
            return "^" + item + "$"; 
        });
    var regexp = new RegExp(regexpArr, 'i');
    $my.isMatched = regexp.test(arrayElem)
    if ($my.isMatched) {
        validatedList.push(elem);  //elem: my object { inside ColumnName, DisplayName }
        AddValidatedList(arrayElem); //arrayElem : elem.ColumnName or elem.DisplayName bla bla.
    }
}

这是有效的.我正在写num*"和即将到来的结果，然后我正在写num|m"和即将到来的结果.因为我使用的是正则表达式，所以我只想支持 '*' 符号.

This is works. I am writing "num*" and coming result and then I am writing "num|m" and coming result. Because I am using regexp so I want to just support '*' sign.

例如:当我写 num* 时，结果应该出现，但我写的 num|m 不应该出现结果.因为我只想支持星号.

For example : When I am writing num*, result should come but I am writing num|m should not come result. Because I want to just support asterisk sign.

我该怎么办?

请有任何想法.

推荐答案

大量借用 这个问题，我认为您在追求以下内容:

Borrowing heavily from this question, I think you are after something like the following:

var checkName =
    checkNames[i]
        .split("*")
        .map(function (s) { return s.replace(/[-\/\\^$*+?.()|[\]{}]/g, '\\$&'); })
        .join(".*");

在分割 * 字符后，这会转义正则表达式的每个部分，准备与 .* 连接起来.

This escapes each part of the regular expression after splitting on the * character, ready to be joined back with .*.

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