我怎样才能得到一个多维数组的单一类型的数组(无环) [英] How can I get the array of a single type from a multi dimensional array (without a loop)
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问题描述
我有以下的数组$ foo的
阵列(10){
[0] =>阵列(4){[MERCHANTID] =>串(5)12e21
[programId] =>串(27)ddd3333
[NETWORKID] => INT(4)
[的clientId] => INT(178)
}
[1] =>阵列(4){[MERCHANTID] =>串(5)112E1
[programId] =>串(27)2vfrdbv1&安培; = 10安培; tmfdpid = CSSS
[NETWORKID] => INT(4)
[的clientId] => INT(178)
}
[2] =>阵列(4){[MERCHANTID] =>串(5)112E1
[programId] =>串(27)2vfrdbv1&安培; = 10安培; tmfdpid = CSSS
[NETWORKID] => INT(4)
[的clientId] => INT(178)
}
和我需要的clientId的数组(只)
是否有可能访问刚刚确定clientid没有循环创建ID的数组?
是这样的:
$ foo的['的clientId']; //不工作
解决方案
在PHP 5.5:
$ rgResult = array_column($ foo的'的clientid');
在PHP< = 5.5:
$ rgResult = array_map(函数($ rgItem)
{
返回$ rgItem ['的clientId'];
} $ foo的);
(把< =
因为这,事业,将在5.5太工作)
I have the following array $foo
array(10) {
[0] => array(4) {
["merchantId"] => string(5) "12e21"
["programId"] => string(27) "ddd3333"
["networkId"] => int(4)
["clientId"] => int(178)
}
[1] => array(4) {
["merchantId"] => string(5) "112e1"
["programId"] => string(27) "2vfrdbv1&=10&tmfdpid=csss"
["networkId"] => int(4)
["clientId"] => int(178)
}
[2] => array(4) {
["merchantId"] => string(5) "112e1"
["programId"] => string(27) "2vfrdbv1&=10&tmfdpid=csss"
["networkId"] => int(4)
["clientId"] => int(178)
}
And I need an array of clientId's (only)
Is it possible to access just the clientId to create an array of id's without a loop?
Something like:
$foo['clientId']; //which doesn't work
解决方案
In PHP 5.5:
$rgResult = array_column($foo, 'clientId');
in PHP <=5.5:
$rgResult = array_map(function($rgItem)
{
return $rgItem['clientId'];
}, $foo);
(put <=
since this, of cause, will work in 5.5 too)
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