REST 服务返回错误的内容类型并解组 [英] REST Service returning wrong content-type and unmarshall
问题描述
我正在使用 RESTEasy,更具体地说,是他们框架的客户端.
I'm using RESTEasy and more specifically, the client side of their framework.
我正在调用第三方 Web 服务,该服务返回一些 JSON 代码.
I'm calling a third part web service that's returning me some JSON code.
但是,出于某些充分的原因,他们响应中的内容类型是text/javascript".
But, for some good reasons, the content-type in their response is "text/javascript".
我如何告诉 RESTEasy 它应该使用 JSON 提供程序(解组目的)用于文本/javascript"内容类型?
How can I tell RESTEasy that it should be using a JSON provider (unmarshalling purposes) for a "text/javascript" content-type ?
这可能吗?
我的代码:
public interface XClient {
@GET
@Produces("application/json")
@Path("/api/x.json")
public Movie getMovieInformation(
@QueryParam("q") String title);
}
解决方案可能是什么样的:
What an solution could be like :
public interface XClient {
@GET
@Produces("text/javascript")
// Tell somehow to use json provider despite the produces annotation
@Path("/api/x.json")
public Movie getMovieInformation(
@QueryParam("q") String title);
}
推荐答案
我的时间不多了,所以这对我有用.我已经将来自服务器的响应标记为字符串,并且我已经使用 Jackson 手动处理了解组:
I'm running out of time, so this did the trick for me. I've marked the response from the server as String, and I've manually handle the unmarshall with Jackson :
public interface XClient {
@GET
@Path("/api/x.json")
@Produces(MediaType.APPLICATION_JSON)
public String getMovieInformation(
@QueryParam("q") String title,
}
并且,在我的 REST 调用中:
and, in my REST call :
MovieRESTAPIClient client = ProxyFactory.create(XClient.class,"http://api.xxx.com");
String json_string = client.getMovieInformation("taken");
ObjectMapper om = new ObjectMapper();
Movie movie = null;
try {
movie = om.readValue(json_string, Movie.class);
} catch (JsonParseException e) {
myLogger.severe(e.toString());
e.printStackTrace();
} catch (JsonMappingException e) {
myLogger.severe(e.toString());
e.printStackTrace();
} catch (IOException e) {
myLogger.severe(e.toString());
e.printStackTrace();
}
如果这不是更好的解决方案,请告知.但这似乎有效.
Please advise if this is not the better solution. But this seems to work.
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