从 Python 中调用 Robot Framework 文件 [英] Calling Robot Framework files from within Python

问题描述

周末忙得不可开交.

我正在尝试创建一个 Python 应用程序，该应用程序将使用户能够运行 .Robot 文件(或测试用例)(从 Python 中)

I am attempting to create a Python Application that will give users the ability to run .Robot files (or Test Cases) (from within Python)

我试图通过使用子进程"模块来运行这些文件，但我不断收到以下错误消息:

I am attempting to run these files through the use of the 'subprocess' module, but I continually receive the following error message :

'FileNotFoundError: [WinError 2] 系统找不到文件指定'

'FileNotFoundError: [WinError 2] The system cannot find the file specified'

我已经包含了导入子流程"

I have included 'import subprocess'

我也将 .Robot 测试用例的位置声明为一个变量:

I have also declared the location of the .Robot Test Case as a variable:

Location = r'C:/Users/verti/PycharmProjects/ChristSax.com/ChristSaxTestSuite/PageSmokeTest.Robot'

在我的代码中，我尝试使用以下语句调用 Robotframework 文件:

Within my code, I've attempted to call the Robotframework file with the following statement :

def AutomatedSmokePage():
    print("Automated Page Smoke Tests now running...")
    subprocess.call(['pybot',Location])

我目前使用的是 Python 3.6.1 和 Robot Framework 3.0.2 版

I am currently using Python 3.6.1 and Robot Framework version 3.0.2

任何帮助将不胜感激.如果您知道完成相同任务的更好方法，请告诉我.

Any help would be appreciated. If you know of a better means to accomplish the same task, please let me know.

推荐答案

让我们假设您在 windows 平台上，并且您要运行的机器人文件在其他目录中

lets assume that you are on windows platform and your robot file which you want t o run is in some other directory

您可以使用子流程模块为您完成下面提到的任务

you can use subprocess module to do the task for you like mentioned below

from subprocess import Popen 
from subprocess import Popen, CREATE_NEW_CONSOLE,PIPE,STDOUT
import platform 
class Server:
    def __init__(self):
        pass
    def run_robotfiles(self,terminal,command1):
        if platform.system()=='Windows':
            self.terminal=terminal
            self.command1=command1
            self.command_server1=self.terminal+' '+self.command1
            self.server1_start=Popen(self.command_server1,creationflags=CREATE_NEW_CONSOLE)

abc=Server()
#you can give path till the robot file or you can use a batch file
#K option tells cmd to run the command and keep the command window from closing. You may use /C instead to close the command window after the command finishes.
abc.run_robotfiles('cmd','/K pybot D:\Users\process.robot')

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