如何将浮点数舍入到给定的精度? [英] How to round float down to a given precision?

问题描述

我需要一种方法将浮点数四舍五入到给定的小数位数，但我想总是向下取整.

例如，代替

<预><代码>>>>回合(2.667, 2)2.67

我宁愿有

<预><代码>>>>round_down(2.667, 2)2.66

解决方案

这样的事情应该适用于你想要做的任何数量的数字:

<预><代码>>>>导入数学>>>def round_down(num,digits):系数 = 10.0 ** 数字返回 math.floor(num * factor)/factor>>>round_down(2.667,2)2.66

I need a way to round a float to a given number of decimal places, but I want to always round down.

For example, instead of

>>> round(2.667, 2)
2.67

I would rather have

>>> round_down(2.667, 2)
2.66

解决方案

Something like this should work for whatever number of digits you want to do:

>>> import math
>>> def round_down(num,digits):
        factor = 10.0 ** digits
        return math.floor(num * factor) / factor

>>> round_down(2.667,2)
2.66

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