如何四舍五入到最接近的 10 次方? [英] How to round down to the nearest power of 10?

问题描述

我什至找不到这方面的搜索关键字.请考虑以下代码:

I can't even find search keywords for this. Please consider this code:

float inputValue = getInputValue();
float resultValue;

if (inputValue < 0.1f) {
    resultValue = 0.01f;
}
else if (inputValue < 1.0f) {
    resultValue = 0.1f;
}
else if (inputValue < 10.0f) {
    resultValue = 1.0f;
}
else {
    resultValue = 10.0f;
}

等等.必须有一种更优雅的方式来做到这一点.我想解决方案很简单，但我现在尝试找到一种方法 2 小时并阅读关于圆形、天花板、地板...找不到它.

and so on. There must be a more elegant way to do this. I guess the solution is easy, but I try to find a way now for 2 hours and read about round, ceil, floor...can't find it.

有人有想法吗?

推荐答案

powf(10.0f, floorf(log10f(value)))

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