从解析Java中的HTTP响应JSON数组 [英] Parsing a JSON Array from HTTP Response in Java

问题描述

我使用Apache的HTTP客户端，我试图解析来自我从客户端得到的回应一个JSON阵列。

这是我收到回JSON的例子。

  [{\"created_at\":\"2013-04-02T23:07:32Z\",\"id\":1,\"password_digest\":\"$2a$10$kTITRarwKawgabFVDJMJUO/qxNJQD7YawClND.Hp0KjPTLlZfo3oy\",\"updated_at\":\"2013-04-02T23:07:32Z\",\"username\":\"eric\"},{\"created_at\":\"2013-04-03T01:26:51Z\",\"id\":2,\"password_digest\":\"$2a$10$1IE6hR4q5jQrYBtyxMJJBOGwSPQpg6m5.McNDiSIETBq4BC3nUnj2\",\"updated_at\":\"2013-04-03T01:26:51Z\",\"username\":\"Sean\"}]
 

我使用 HTTP：//$c$c.google.com/ p / JSON-简单/ 我的JSON库。

  HttpPost httppost =新HttpPost（SERVERURL）;
        httppost.setEntity（输入）;
        HTT presponse响应= httpclient.execute（httppost）;
        RD的BufferedReader =新的BufferedReader（新的InputStreamReader（response.getEntity（）的getContent（）））        对象物obj = JSONValue.parse（rd.toString（））;
        JSONArray finalResult =（JSONArray），其中OBJ;
        的System.out.println（finalResult）;
 

下面是code我都试过，但它不工作。我真的不知道该怎么做。任何帮助是AP preciated，谢谢。

解决方案

  

的BufferedReader RD =新的BufferedReader（新的InputStreamReader（response.getEntity（）的getContent（）））
  obj对象= JSONValue.parse（rd.toString（））;

rd.toString（）不会给你的，内容的InputStream 对应 response.getEntity（）的getContent（）。相反，它给人的的toString（）再一个的BufferedReader 对象presentation。尝试打印它在控制台上，看看它是什么。

相反，你应该从读取数据的BufferedReader 如下：

  StringBuilder的内容=新的StringBuilder（）;
串线;
而（空！=（线= br.readLine（））{
    content.append（线）;
}
 

然后，您应该分析具体内容，以获得JSON阵列。

  obj对象= JSONValue.parse（content.toString（））;
JSONArray finalResult =（JSONArray），其中OBJ;
的System.out.println（finalResult）;
 

I am using the HTTP client from Apache, and am trying to parse a JSON array from the response I get from the client.

This is an example of the JSON I receive back.

 [{"created_at":"2013-04-02T23:07:32Z","id":1,"password_digest":"$2a$10$kTITRarwKawgabFVDJMJUO/qxNJQD7YawClND.Hp0KjPTLlZfo3oy","updated_at":"2013-04-02T23:07:32Z","username":"eric"},{"created_at":"2013-04-03T01:26:51Z","id":2,"password_digest":"$2a$10$1IE6hR4q5jQrYBtyxMJJBOGwSPQpg6m5.McNDiSIETBq4BC3nUnj2","updated_at":"2013-04-03T01:26:51Z","username":"Sean"}]

I am using http://code.google.com/p/json-simple/ as my json library.

        HttpPost httppost = new HttpPost("SERVERURL");
        httppost.setEntity(input);
        HttpResponse response = httpclient.execute(httppost);
        BufferedReader rd = new BufferedReader(new InputStreamReader(response.getEntity().getContent()))

        Object obj=JSONValue.parse(rd.toString());
        JSONArray finalResult=(JSONArray)obj;
        System.out.println(finalResult);

Here is the code I have tried but it doesn't work. I am not really sure what to do. Any help is appreciated, thanks.

解决方案

BufferedReader rd = new BufferedReader(new InputStreamReader(response.getEntity().getContent())) Object obj=JSONValue.parse(rd.toString());

rd.toString() would not give you the content of that InputStream corresponding to response.getEntity().getContent(). It instead gives the toString() representation of a BufferedReader object. Try printing it on your console to see what it is.

Instead you should read the data from the BufferedReader as follows:

StringBuilder content = new StringBuilder();
String line;
while (null != (line = br.readLine()) {
    content.append(line);
}

Then, you should parse the content to get the JSON array.

Object obj=JSONValue.parse(content.toString());
JSONArray finalResult=(JSONArray)obj;
System.out.println(finalResult);

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