使用 rpy2 将 .R 文件导入 python 的问题 [英] problems sourcing in an .R file into python using rpy2

问题描述

在 rpy 1.x 中，要在 .R 文件中获取源代码，您只需要做的就是:

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导入 rpyrpy.r.source("文件名.R")

在 rpy2 中，要从 Python 获取 .R 文件需要做什么?

我尝试了多种途径，例如:

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import rpy2.robjects as roro.source("文件名.R")

返回这样的错误(抱歉，如果格式不正确):

文件C:\Python27\lib\site-packages\rpy2\robjects\functions.py"，第 166 行，在 __call__ 中return super(SignatureTranslatedFunction, self).__call__(*args, **kwargs)文件C:\Python27\lib\site-packages\rpy2\robjects\functions.py"，第 99 行，在 __call__ 中res = super(Function, self).__call__(*new_args, **new_kwargs)RRuntimeError:文件错误(文件名，r"，编码 = 编码):无法打开连接

提前致谢...

解决方案

您应该能够使用rpy2.robjects.r()(或.R()<)运行任意R代码/code>，不要觉得有区别):

import rpy2.robjects as roro.r("""source('文件名.R')""")

我会首先在 RStudio(或您的首选替代方案)中测试 filename.R，以确保它是一个有效文件并且可以毫无问题地获取.

In rpy 1.x, to source in a .R file, all one had to do was this:

import rpy 
rpy.r.source("filename.R")

In rpy2, what needs to happen in order to source in a .R file from Python?

I have tried several avenues, such as this:

import rpy2.robjects as ro
ro.source("filename.R")

Returns an error like this (sorry if this doesn't format correctly):

File "C:\Python27\lib\site-packages\rpy2\robjects\functions.py", line 166, in __call__
return super(SignatureTranslatedFunction, self).__call__(*args, **kwargs)
File "C:\Python27\lib\site-packages\rpy2\robjects\functions.py", line 99, in __call__
res = super(Function, self).__call__(*new_args, **new_kwargs)
RRuntimeError: Error in file(filename, "r", encoding = encoding) : 
cannot open the connection

Thanks in advance...

解决方案

You should be able to run arbitrary R code with rpy2.robjects.r() (or .R(), don't think there's a difference):

import rpy2.robjects as ro

ro.r("""source('filename.R')""")

I'd test filename.R first in RStudio (or your preferred alternative) first, just to make sure it's a valid file and can be sourced without issues.

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