Regexp.last_match 线程安全吗? [英] Is Regexp.last_match thread safe?

问题描述

这是我正在查看的代码:

This is the code that I'm looking at:

def method_missing(id, *args)
    return self.find(Regexp.last_match(1),  args[0]) if id.id2name =~ /find_by_(.+)/
    raise NoMethodError
end

如果我有多个线程调用 Regexp.last_match 会怎样?

What happens if I have multiple threads calling Regexp.last_match?

如果我有多个线程使用 method_missing 方法调用对象会怎样?

What happens if I have multiple threads calling the object with the method_missing method?

推荐答案

Ruby 1.9.2 平台文档声明调用 Regexp.last_match 等效于读取特殊的 $~ 全局变量.

The Ruby 1.9.2 platform docs state that calling Regexp.last_match is equivalent to reading the special $~ global variable.

来自The Ruby Programming Language"，第 318 页:重要的是要记住 $~ 和从它派生的变量都是线程局部和方法局部的."

From "The Ruby Programming Language", pg 318: "it is important to remember that $~ and the variables derived from it are all thread-local and method-local."

所以 Regexp.last_match 是 线程安全的.至于您在 method_missing 中使用的其他方法，我相信它们也是线程安全的.(如果有人知道不同，请编辑此帖子.)

So Regexp.last_match is thread-safe. As for the other methods you are using in method_missing, I believe they are thread-safe as well. (If anybody knows differently, please edit this post.)

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