返回空数组(Ruby) [英] Return empty array (Ruby)

问题描述

我正在尝试在 Ruby 中创建条件语句.如果我的各种数字数组为空或 nil，它应该返回一个空数组，否则它应该对数字进行排序.这是我目前所拥有的.

I am trying to create a condition statement in Ruby. If my array of various numbers is empty or nil, it should return an empty array otherwise it should sort the numbers. This is what I have so far.

num == nil || num.empty? ? return num : num.sort!

...其中 num 是我的数组.但是我收到以下错误:

...where num is my array. However I'm getting the following error:

syntax error, unexpected tIDENTIFIER, expecting ':'

如果 num 是数字数组或 nil，我会收到此错误.我不确定为什么这不起作用.有什么想法吗?

I get this error if num is an array of numbers or nil. I'm not sure why this isn't working. Any thoughts?

推荐答案

要修复您的代码，请将您拥有的内容更改为以下内容之一:

To fix your code, change what you have to one of the following:

num.nil? || num.empty? ? [] : num.sort

num.nil? ? [] : num.sort

(num || []).sort

num.to_a.sort

如果num为nil，后两者将num转换为空数组，然后对结果进行排序.请参阅 NilClass.to_a.

The latter two convert num to an empty array if num is nil, then sort the result. See NilClass.to_a.

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