使用 Rails 即时生成独特的令牌 [英] Generating unique token on the fly with Rails

问题描述

我想在我的控制器中为user_info_token"列中的用户生成一个令牌.但是，我想检查当前没有用户拥有该令牌.这段代码就够了吗?

I want to generate a token in my controller for a user in the "user_info_token" column. However, I want to check that no user currently has that token. Would this code suffice?

  begin
    @new_token = SecureRandom.urlsafe_base64 
    user = User.find_by_user_info_token(@new_token) 
  end while user != nil 

  @seller.user_info_token = @new_token 

或者有更简洁的方法来做到这一点吗?

Or is there a much cleaner way to do this?

推荐答案

我找到的最干净的解决方案:

The cleanest solution I found:

@seller.user_info_token = loop do
  token = SecureRandom.urlsafe_base64
  break token unless User.exists?(user_info_token: token)
end

一些非常干净但可能重复的东西(虽然很少):

And something very clean but with potential duplicates (very few though):

@seller.user_info_token = SecureRandom.uuid

重复的随机 UUID 概率

当然，为您的 :user_info_token 添加唯一索引.搜索具有相同令牌的用户会更快并且如果偶然有 2 个用户在同一时刻使用完全相同的令牌被保存，它将引发异常！

of course, add a unique index to your :user_info_token. It will be much quicker to search for a user with the same token and it will raise an exception if by chance, 2 users are saved at the exact same moment with the exact same token!

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