按整数值对字符串数组进行排序 [英] Sort an Array of Strings by their Integer Values

问题描述

假设我有一个从 1 到 10 的未排序数组，如下所示...

Let's say I have an unsorted array from 1 to 10, as shown below...

a = ["3", "5", "8", "4", "1", "2", "9", "10", "7", "6"]

如果我在这个数组上使用 sort 方法，它会返回这个...

If I use the sort method on this array, it returns this...

a.sort = ["1", "10", "2", "3", "4", "5", "6", "7", "8", "9"]

如您所见，10 出现在 2 之前，这是不正确的.如何对这些数字进行排序，以便 10 正确显示?

As you can see, the 10, appears before the 2, which is incorrect. How can I sort these numbers so that 10 appears correctly?

谢谢大家的回复.我应该更好地解释我的问题.我需要排序的数组用于电子商务价格表.于是数组出现如下...

Thank you all for your responses. I should explain my problem a little better. The array I need sorted is for an e-commerce price list. So the array appears as follows...

a = ["0-10", "11-20", "21-30", "31-40" etc.]

所以字符串不能转换为整数.当我写这个问题时，我应该把这个写出来.我不认为修复会有太大差异.我的错误，我为做出这个假设而道歉！我怎样才能对这个数组进行排序?谢谢！

So the strings cannot be converted to integers. I should have put this when I wrote the question. I did not think that there would be much difference in the fix. My mistake, I apologise for making this assumption! How though can I sort this array? Thanks!

推荐答案

我会抛出另一种方法，因为这是我能想到的最短方法

I'll throw another method out there since it's the shortest way I can think of

a.sort_by(&:to_i)

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