如何在 Slim 模板中渲染 HTML [英] How to render HTML inside Slim templates

问题描述

我正在尝试呈现以图标开头的链接.我正在使用 Slim 模板引擎和 Bootstrap CSS.

I'm trying to render a link preceded by an icon. I'm using Slim templating engine along with Bootstrap CSS.

通常您可以通过以下方式执行此操作:

Usually you could do this the following way:

<a href="#"><i class="icon-user"></i> My Profile</a>

根据 Slim 的文档，我们可以使用 == 进行渲染而无需转义 HTML.因此，将其转换为 Slim，我尝试了以下变体:

According to Slim's documentation, we can use == to render without escaping HTML. So, translating this to Slim, I tried the following variations:

li== link_to "<i class='icon-user'></i> My Profile", current_user
li== link_to "#{'<i class="icon-user"></i>'.html_safe} My Profile", current_user
li= link_to "#{'<i class="icon-user"></i>'.html_safe} My Profile", current_user

呈现的所有变体<a href="/users/1"><i class="icon-user"></i>我的个人资料 转义 i 标签.

All variations rendered <a href="/users/1"><i class="icon-user"></i> My Profile</a> escaping the i tag.

如何阻止 Slim 或 Rails 转义 html?

How can I stop Slim or Rails from escaping html?

(Rails 3.2 与 Slim 1.2.1)

(Rails 3.2 with Slim 1.2.1)

推荐答案

您想禁用 link_to 参数的 HTML 转义，而不是整个 link_to 结果.您与 html_safe 非常接近，但是您的字符串插值正在吞噬您的HTML 安全"标志.这应该会更好:

You want to disable HTML escaping for the link_to argument, not the entire link_to result. You're pretty close with your html_safe but your string interpolation is eating your "safe for HTML" flag. This should work better:

li= link_to '<i class="icon-user"></i> My Profile'.html_safe, current_user

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