正则表达式:如果字符串包含空格则不匹配 [英] Regex: don't match if string contains whitespace

问题描述

我似乎无法找出匹配字符串的正则表达式模式，仅当它不包含空格时.例如

I can't seem to figure out the regex pattern for matching strings only if it doesn't contain whitespace. For example

"this has whitespace".match(/some_pattern/)

应该返回 nil 但是

"nowhitespace".match(/some_pattern/)

应该返回带有整个字符串的 MatchData.任何人都可以为上述问题提出解决方案吗?

should return the MatchData with the entire string. Can anyone suggest a solution for the above?

推荐答案

在 Ruby 中我认为是

In Ruby I think it would be

/^\S*$/

这意味着开始，匹配任意数量的非空白字符，结束"

This means "start, match any number of non-whitespace characters, end"

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