分割线进入的话+ C数组 [英] Split line into array of words + C

问题描述

我试图分割线成词的数组，但我被困在如何做到这一点的C.我用C技能不是很好，所以我不能想办法执行我的想法。她是我迄今为止：

  INT beginIndex = 0;
INT endIndex的= 0;
INT maxWords = 10;
而（1）{
   而（！isspace为（STR））{
      endIndex的++;
   }
   字符* TMP =（String一个从beginIndexSTR到endIndex）
   ARR [wordCnt] = tmp目录;
   wordCnt ++;
   beginIndex = endIndex的;
   如果（wordCnt = maxWords）{
       返回;
   }
}
 

在我的方法，我收到（的char * str中，字符* ARR [10]），和STR是，我想，当我遇到一个空间分割线。 ARR是我要存储字阵列。有什么办法字符串的'块'，我是从'海峡'想复制到我的TMP变量？这是我现在能想到的最好的办法，也许这是一个可怕的想法。如果是这样，我会很乐意得到一些文件或提示上更好的方法。

解决方案

 的#include＆LT;＆stdio.h中GT;
＃包括LT＆;＆stdlib.h中GT;
＃包括LT＆;＆string.h中GT;
＃包括LT＆;＆文件ctype.h GT;INT拆分（的char * str中，字符* ARR [10]）{
    INT beginIndex = 0;
    INT endIndex的;
    INT maxWords = 10;
    INT wordCnt = 0;    而（1）{
        而（isspace为（STR [beginIndex]））{
            ++ beginIndex;
        }
        如果（STR [beginIndex] =='\\ 0'）
            打破;
        endIndex的= beginIndex;
        而（STR [endIndex的＆放大器;＆安培;！isspace为（STR [endIndex的]））{
            ++ endIndex的;
        }
        INT LEN = endIndex的 -  beginIndex;
        字符* TMP =释放calloc（LEN + 1的sizeof（字符））;
        的memcpy（TMP，＆安培; STR [beginIndex]，LEN）;
        ARR [wordCnt ++] = tmp目录;
        beginIndex = endIndex的;
        如果（wordCnt == maxWords）
            打破;
    }
    返回wordCnt;
}诠释主要（无效）{
    字符* ARR [10];
    INT I;
    INT N =拆分（第一第二第三，ARR）;    对于（i = 0; I＆LT; N ++我）{
        看跌期权（ARR [I]）;
        免费（ARR [I]）;
    }    返回0;
}
 

I am trying to split a line into an array of words, but I am stuck on how to do this in C. My skills in C aren't very good, so I can't think of a way to "execute" my idea. Her is what I have so far:

int beginIndex = 0;
int endIndex = 0;
int maxWords = 10;
while (1) {
   while (!isspace(str)) {
      endIndex++;
   }
   char *tmp = (string from 'str' from beginIndex to endIndex)
   arr[wordCnt] = tmp;
   wordCnt++;
   beginIndex = endIndex;
   if (wordCnt = maxWords) {
       return;
   }
}

In my method I receive (char *str, char *arr[10]), and str is the line that I want to split when I encounter a space. arr is the array where I want to store the words. Is there any way to copy the 'chunk' of string that I want from 'str' into my tmp variable? This is the best way that I can think of right now, perhaps it's a terrible idea. If so, I would be happy to get some documentation or tips on a better method.

解决方案

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>

int split(char *str, char *arr[10]){
    int beginIndex = 0;
    int endIndex;
    int maxWords = 10;
    int wordCnt = 0;

    while(1){
        while(isspace(str[beginIndex])){
            ++beginIndex;
        }
        if(str[beginIndex] == '\0')
            break;
        endIndex = beginIndex;
        while (str[endIndex] && !isspace(str[endIndex])){
            ++endIndex;
        }
        int len = endIndex - beginIndex;
        char *tmp = calloc(len + 1, sizeof(char));
        memcpy(tmp, &str[beginIndex], len);
        arr[wordCnt++] = tmp;
        beginIndex = endIndex;
        if (wordCnt == maxWords)
            break;
    }
    return wordCnt;
}

int main(void) {
    char *arr[10];
    int i;
    int n = split("1st 2nd 3rd", arr);

    for(i = 0; i < n; ++i){
        puts(arr[i]);
        free(arr[i]);
    }

    return 0;
}

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