如何从 Rails 中的模型渲染视图? [英] how to render a view from the model in Rails?

问题描述

我必须编辑 Rails 应用程序，但在语言方面我是新手(我是 Ruby 和 Rails 的新手).在查看源文件时，我提出了一些问题:

I have to edit a Rails application, but I am a novice when it comes to language (I am new to Ruby & Rails). When viewing the source files I raised some questions:

class Card < ActiveRecord::Base
    class CardRenderer < AbstractController::Base
        include AbstractController::Rendering
        include AbstractController::Helpers

        self.view_paths = Rails.application.config.paths["app/views"]

        helper_method :res_url

        def print(_card, _template)
             @card = _card
             render template: "prints/#{_template}.html"
        end

        protected
            def res_url(_res_name)
                "#{Rails.root}/app/views/prints/res/#{_res_name}"
            end
     end
     .......
     .......
     .......
end

我看到一个模型在另一个类中包含一个类你有这个语言功能的名字吗?

I saw a model that contained a classe inside another class Do you have a name this language feature?

如何从模型的实例调用这个类?例如来自控制器(显然这不起作用):

How I can call this class from an instance of the model? for example from the controller (Obviously this does not work):

@card::CardRenderer.new.print(@card, @template)

模型类里面的类有一个渲染视图的函数

The class that is inside the model class has a function that renders a view

我可以从控制器使用这个功能吗?例如来自控制器(显然这也不起作用)

I can make use this function from the controller? for example from the controller (obviously this does not work either)

render Card::CardRenderer.new.print(@card, @template)

理想的是我读一本书！，我会做到的！但在这些日子里我不能(时间问题).

Is that the ideal is that I read a book!, And I'll do it! but in these days I can not (timing problems).

推荐答案

您有此语言功能的名称吗?

嵌套类"，我认为

如何从模型的实例调用这个类?

@card.class::CardRenderer 应该可以工作

模型类中的类有一个渲染视图的函数.我可以从控制器使用这个功能吗?

从头到尾阅读全文:http://guides.rubyonrails.org/layouts_and_rendering.html

附言我偷偷怀疑应用程序的当前设计完全违背了模型-视图-控制器的想法

p.s. I have a sneaking suspicion the current design of the app goes completely against the ideas of Model-View-Controller

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