有没有办法将迭代器解包成元组? [英] Is there any way to unpack an iterator into a tuple?

问题描述

有什么方法可以完成如下操作:

Is there any way to accomplish something like the following:

let v = vec![1, 2, 3];
let (a, b) = v.iter().take(2);

这样，最后是 a = 1 和 b = 2 吗?

Such that a = 1 and b = 2 at the end?

我知道我可以只使用向量，但我想要命名变量.

I know I could just use a vector but I would like to have named variables.

推荐答案

这可能不是您所要求的，但我想您很少想将任意大的向量转换为元组.如果只想将向量的前几个元素提取到元组中，可以使用切片模式匹配:

This may not be exactly what you asked for, but I suppose you rarely want to convert an arbitrarily large vector to a tuple anyway. If you just want to extract the first few elements of a vector into a tuple, you can do so using slice pattern matching:

fn main() {
    let v = vec![1, 2, 3];
    let (a, b) = match &v[..] {
        &[first, second, ..] => (first, second),
        _ => unreachable!(),
    };
    assert_eq!((a, b), (1, 2));
}

这篇关于有没有办法将迭代器解包成元组?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！