如何可变数量的参数传递给在PHP函数 [英] How to pass a variable number of parameters to a function in PHP

问题描述

我有这个多维数组（称为$值）：

I have this multidimensional array (called $values):

Array
(
    [0] => Array
        (
            [0] => 5
            [1] => 2
            [2] => 5
            [3] => 6
        )

    [1] => Array
        (
            [0] => 3
            [1] => 4
            [2] => 5
            [3] => 6
        )

    [2] => Array
        (
            [0] => 1
            [1] => 2
            [2] => 4
            [3] => 5
        )

    [3] => Array
        (
            [0] => 9
            [1] => 5
            [2] => 3
            [3] => 2
        )
)

我想用和array_diff PHP函数这个多维数组的每一个元素（数组）之间来计算差异。我想的第一件事就是到多维数组为单个阵列，这种分裂：

I want to calculate the diff between every element (array) of this multidimensional array using array_diff PHP function. The first thing I've thought is to split the multidimensional array into single arrays with this:

for($cnt = 0; $cnt < count($values); $cnt++){
        for($cntB = 0; $cntB < 4; $cntB++){
            ${'arr'.$cnt}[] = $values[$cnt][$cntB];
        }
    }

这之后，我有几个阵列名为 $ ARR1 ， $ ARR2 ，等等。由于阵列的尺寸 $值可能会有所不同（它将）我不能找到一种方法，所有生成的单数组传递给函数和array_diff ，

After this I have several arrays called $arr1, $arr2, and so on. Since the dimension of the array $values may vary (and it will) I can't find a way to pass all the generated single arrays to the function array_diff,

有什么想法？

先谢谢了。

推荐答案

不知道这是你想要的，因为我没看过所有这一切，但检查出来：

Not sure if this is what you want, as I didn't read all of that, but check out:

call_user_func_array('array_diff', $values)

也许这就是你想要的。

Maybe that's what you want.

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