变长数组的数组 [英] Array of Variable Length Arrays

问题描述

通常情况下，我们可以这样写：

 为const char * names1 [] = {栈，LongerThanStack};
为const char * names2 [] = {溢出，LongerThanOverflow，O};
 

如何使一个新的数组名称包含上述两个数组？

二维数组应该这样做。
我尝试以下code，但 G ++ 并没有接受，因为内部数组的长度可变的。

 为const char *名称[2] [] = {{栈，LongerThanStack}，
                    {溢出，LongerThanOverflow，O}};
 

解决方案

除非你有一个pressing不需要，像这样做：

 的std ::矢量＆lt;的std ::矢量＆lt;标准::字符串＆GT;＆GT;名字= {{栈，LongerThanStack，S}，{溢出，LongerThanOverflow，O}};
 

Normally, we can write this :

const char* names1[] = { "Stack", "LongerThanStack" };
const char* names2[] = { "Overflow", "LongerThanOverflow", "O" };

How to make a new array names that contains the above two arrays ?

Two dimensional arrays should do this. I tried the following code, but G++ didn't accept it because of the variable length of the inner array.

const char* names[2][] = {{ "Stack", "LongerThanStack" }, 
                    { "Overflow", "LongerThanOverflow", "O" }};

解决方案

Unless you have a pressing need not to, do it like this:

std::vector<std::vector<std::string>> names = {{ "Stack", "LongerThanStack", "S" }, { "Overflow", "LongerThanOverflow", "O" }};

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