检查一些已经在一个阵列中使用的Java [英] to check if a number have already been used in a array java

问题描述

接听的评论：
是的，我知道我没有搜索任何东西。我不知道怎么了，那种原因我在这里
不，我不需要你写从我的code，只需告诉我它是怎么做的，所以我可以学习
我曾尝试不同的东西，但不想乱了我的code的东西，没有工作。

问题：我需要检查，如果输入已经被使用过，如果不是我想将它添加到阵列中，如果不是我想再问

。

 扫描仪键盘=新的扫描仪（System.in）;的System.out.println（什么是数组的长度？）;
INT lengde = keyboard.nextInt（）;
INT [] myArray的=新的INT [lengde]
的for（int i = 0; I＆LT; lengde;我++）{
  的System.out.println（第（i + 1）+（给一个号码））;
  INT使用= keyboard.nextInt（）;  //如果在使用前已经添加
   //的System.out.println（选择一个新号码）;  // //其他使用前没有被添加
    myArray的[我] =使用;}
对于（INT I：myArray的）
  的System.out.println（ⅰ）;keyboard.close（）;
 

解决方案

检查情况如下最简单的方式：

 的for（int i = 0; I＆LT; lengde;）{
  INT的readInt = keyboard.nextInt（）;
  布尔发现= FALSE;
  对于（INT指数= 0;指数 -  LT;我;指数++）{
    intFromArray = myArray的[指数] //从数组元素
    如果（==的readInt intFromArray）{
      发现= TRUE; //号码已在阵
      打破;
    }
  }
  //在数组中没有发现的数量。将它添加到阵列。
  如果（！找到）{
    myArray的[I] =的readInt;
    我++;
  }其他{
       的System.out.println（阵中找到再试一次......。）;
  }}
 

您可能希望允许一定数量的唯一的尝试，否则会无限循环。

Answering the comments: Yes, I do know I have not searched for anything. I don't know how, kind of the reason I am here No, I don't need you to write the code from me, simply show me how it is done so I can learn I have tried different things, but did not want to mess my code with things that did not work

question: I need to check if the input have been used before, If not I want to add it to the array, if not I want to ask again.

Scanner keyboard = new Scanner(System.in);

System.out.println("What's the length of the array?");
int lengde = keyboard.nextInt();                   
int[] myArray = new int[lengde]; 


for (int i = 0; i < lengde; i++) {
  System.out.println((i+1) + (" give a number"));
  int used = keyboard.nextInt(); 

  //if  used have been added before
   // System.out.println("pick a new number");

  //else // used have not been added before
    myArray[i] = used;

} 
for (int i : myArray)
  System.out.println(i);

keyboard.close();

解决方案

The simplest way to check would be as follows:

for (int i = 0; i < lengde; ) {
  int readInt = keyboard.nextInt();
  boolean found = false;
  for(int index=0; index < i; index++) {
    intFromArray = myArray[index]; // Get element from array
    if(readInt == intFromArray) {
      found = true; // Number already in array
      break;
    }
  }
  // Number not found in the array. Add it to the array.
  if(!found) {
    myArray[i] = readInt;
    i++;
  } else {
       System.out.println("Found in array. Try again...");
  }

}

You might want to allow a certain number of tries only, otherwise it will loop indefinitely.

这篇关于检查一些已经在一个阵列中使用的Java的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！