Scala:将 Seq 传递给 var-args 函数 [英] Scala: pass Seq to var-args functions

问题描述

给定一个接受可变数量参数的函数，例如

Given a function that takes a variable number of arguments, e.g.

def foo(os: String*) =
  println(os.toList)

如何将参数序列传递给函数?我想写:

How can I pass a sequence of arguments to the function? I would like to write:

val args = Seq("hi", "there")
foo(args)

显然，这是行不通的.

推荐答案

foo(args:_*) 可以解决问题.序列中的每个元素都将用作一个参数，而不是将序列作为单个参数应用.

foo(args:_*) does the trick. Instead of applying the sequence as one single argument, each element in the sequence will be used as an argument.

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