如何在scala中编写函数isFunction? [英] How to write the function isFunction in scala?

问题描述

我如何在 Scala 中编写 isFunction 函数，以使其有效:

How can i write a isFunction function in scala, so that this works:

def isFunction(x:Any) = /* SomeCode */

println(isFunction(isFunction _)) //true
println(isFunction("not a function")) //false

推荐答案

很丑，但它有效:

def isFunction(x:Any) = x match {
  case _: Function0[_] => true
  case _: Function1[_, _] => true
  case _: Function2[_, _, _] => true
  ...
  case _: Function22[...] => true
  case _: PartialFunction[_, _] => true
  case _ => false
}

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