Scala Split Seq 或 List by Delimiter [英] Scala Split Seq or List by Delimiter

问题描述

假设我有一个这样的整数序列:

Let's say I have a sequence of ints like this:

val mySeq = Seq(0, 1, 2, 1, 0, -1, 0, 1, 2, 3, 2)

我想将其拆分为 0 作为分隔符，如下所示:

I want to split this by let's say 0 as a delimiter to look like this:

val mySplitSeq = Seq(Seq(0, 1, 2, 1), Seq(0, -1), Seq(0, 1, 2, 3, 2))

在 Scala 中执行此操作最优雅的方法是什么?

What is the most elegant way to do this in Scala?

推荐答案

这个没问题

mySeq.foldLeft(Vector.empty[Vector[Int]]) {
  case (acc, i) if acc.isEmpty => Vector(Vector(i))
  case (acc, 0) => acc :+ Vector(0)
  case (acc, i) => acc.init :+ (acc.last :+ i)
}

其中 0(或其他)是您的分隔符.

where 0 (or whatever) is your delimiter.

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