将字符串拆分为交替单词(Scala) [英] Split String into alternating words (Scala)

问题描述

我想将一个字符串拆分成交替的单词.总会有偶数.

I want to split a String into alternating words. There will always be an even number.

例如

val text = "this here is a test sentence"

应该转换为一些有序的集合类型，包含

should transform to some ordered collection type containing

"this", "is", "test"

和

"here", "a", "sentence"

我想出了

val (l1, l2) = text.split(" ").zipWithIndex.partition(_._2 % 2 == 0) match {
  case (a,b) => (a.map(_._1), b.map(_._1))}

这给了我正确的结果作为两个数组.

which gives me the right results as two Arrays.

这能做得更优雅吗?

推荐答案

scala> val s = "this here is a test sentence"
s: java.lang.String = this here is a test sentence

scala> val List(l1, l2) = s.split(" ").grouped(2).toList.transpose
l1: List[java.lang.String] = List(this, is, test)
l2: List[java.lang.String] = List(here, a, sentence)

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