为 fscanf 指定不包含空格的格式 [英] Specifying a format for fscanf that doesn't contain white-spaces

问题描述

我正在尝试使用 fscanf() 从 c 中的文本文件中读取名称.但是，此文件中的名称不以空格分隔.我还能用这个函数把每个名字分开吗?

I am trying to use fscanf() to read names from a text file in c. However, the names in this file are not separated by white-spaces. Can I still separate out each name using this function?

目前，该文件包含此文本:

At the moment, the file contains this text :

"MARY","PATRICIA"

当我运行以下代码时:

FILE *nameFile;
char name1[100];
char name2[100];

nameFile = fopen("names.txt","r");

fscanf(nameFile, "%s,%s", name1, name2);
printf("name 1 : %s\n name 2 :%s\n", name1, name2);

fclose(nameFile);

我得到以下输出:

name1: "MARY","PATRICIA"
name2:

有没有办法在文件中没有空格的情况下将名称分开?

Is there any way of separating the names out without having spaces in the file?

推荐答案

你必须指示 fscanf() 寻找另一个分隔符，切割字段(使用 %[ 格式化程序).

You have to instruct the fscanf() to look for another delimiter, cutting the fields (using %[ formatter).

请试试这个:

#include <stdio.h>

int main(int argc, char *argv[])
{
   FILE *nameFile;
   char name1[100];
   char name2[100];

   nameFile = fopen("names.txt","r");
   fscanf(nameFile, "%[^,],%[^,]\n", name1, name2);
   /* or fscanf(nameFile, "%[^,],%s\n", name1, name2); for second string */

   printf("name 1 : %s\n name 2 :%s\n", name1, name2);

   fclose(nameFile);

   return(0);
}

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