为什么 sscanf 不处理或忽略 C++ 中的空格? [英] Why sscanf is not handling or ignoring spaces in c++?

问题描述

我有以下行要放在 sscanf 中，但它不接受空格

I have the following line to be put up in sscanf but its not accepting white spaces

char store_string[25],store_string1[10];
std::tm t={};
int store_integer,store_integer1,store_integer2;
int total_read;
           
char* buff1 = "Demo to dispay (Appname,App usage) with date (03/11/2005) with test id (87773) data added (0) total ((null))";
char* buff2 = "Demo to dispay %s with date (%d/%d/%d) with test id (%d) data added (%d) total ((%d))";
            
total_read = sscanf(buff1, buff2 , store_string,  &t.tm_mon,
&t.tm_mday,
&t.tm_year,
&store_integer,&store_integer1,&store_integer2);

   

输出:

如果 buff1 有显示 (Appname,Appusage) 它工作正常

if buff1 has display (Appname,Appusage) it works fine

但是如果 buff1 有显示 (Appname,App usage) 它失败了

But If buff1 has display (Appname,App usage) it fails

推荐答案

为什么 sscanf 不处理或忽略 C++ 中的空格?

Why sscanf is not handling or ignoring spaces in c++?

sscanf 还应该如何分离单词/标记?来自其文档:

How else should sscanf seperate words/tokens? From its documentation:

[%s"] 匹配一系列非空白字符(字符串)

["%s"] matches a sequence of non-whitespace characters (a string)

我认为您无法使用 sscanf 或单行代码来处理此问题.您可以使用 std::string::find_first_of 和 std::string::substr

I don't think you can handle this with sscanf or in a one-liner at all. You could do this with std::string::find_first_of and std::string::substr

std::regex_match 可能是最灵活和可读的方式，如果你已经习惯了正则表达式.

std::regex_match might be the most flexible and readable way if you're used to regular expressions.

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