旋转 SCNNode 相对本地坐标 [英] Rotate SCNNode relative local coordinates

问题描述

我试图通过 SCNAction 旋转一个节点，但它相对于父节点的坐标空间旋转.是否可以相对于本地坐标系旋转节点?

解决方案

好的.您可以使用 convertVector 方法获取旋转轴的父空间坐标.>

例如，此动作将围绕局部 x 轴旋转 180 度:

SCNAction.rotate(by: .pi, around: node.convertVector(SCNVector3(1, 0, 0), to: node.parent), duration: TimeInterval(5))

I'm trying to rotate a node by SCNAction, but it rotates relative to parent’s coordinate space. Is it possible to rotate a node relative local's coordinate system?

解决方案

Sure. You can obtain parent's space coordinates for rotation axis with convertVector method.

For example, this action will do 180 degrees rotation around local x-axis:

SCNAction.rotate(by: .pi, around: node.convertVector(SCNVector3(1, 0, 0), to: node.parent), duration: TimeInterval(5))

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