如何每小时调用一次函数?另外,我怎样才能循环这个? [英] How to call function every hour? Also, how can I loop this?
问题描述
我需要一种简单的方法来每 60 分钟调用一次函数.我怎样才能做到这一点?我正在制作一个 MineCraft bukkit 插件,这就是我所拥有的:
I need a simple way to call a function every 60 minutes. How can I do this? I'm making a MineCraft bukkit plugin, and this is what I have:
package com.webs.playsoulcraft.plazmotech.java.MineRegen;
import java.util.logging.Logger;
import org.bukkit.Location;
import org.bukkit.block.Block;
import org.bukkit.event.block.Action;
import org.bukkit.event.player.PlayerInteractEvent;
import org.bukkit.plugin.java.JavaPlugin;
public class Main extends JavaPlugin{
public final Logger log = Logger.getLogger("Minecraft");
@Override
public void onEnable() {
this.log.info("~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~");
this.log.info("Plaz's Mine Regen is now enabled!");
this.log.info("Copyright 2012 Plazmotech Co. All rights reserved.");
this.log.info("~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~");
}
@Override
public void onDisable() {
this.log.info("~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~");
this.log.info("Plaz's Mine Regen is now disabled!");
this.log.info("Copyright 2012 Plazmotech Co. All rights reserved.");
this.log.info("~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~");
}
public void onPlayerInteract(PlayerInteractEvent event) {
final Action action = event.getAction();
if (action == Action.LEFT_CLICK_BLOCK) {
Location l1 = event.getClickedBlock().getLocation();
} else if (action == Action.RIGHT_CLICK_BLOCK) {
Location l2 = event.getClickedBlock().getLocation();
}
}
}
我需要运行一个我将每小时执行一次的函数,怎么做?请记住:该函数将使用 l1 和 l2.另外,我怎样才能循环这个以获得中间的每个块?
I need to run a function I will implement every hour, how? Remember: The function will use l1, and l2. Also, how can I loop this to get every block inbetween?
推荐答案
创建一个 Timer
对象并给它一个 TimerTask
来执行你想要执行的代码.
Create a Timer
object and give it a TimerTask
that performs the code you'd like to perform.
Timer timer = new Timer ();
TimerTask hourlyTask = new TimerTask () {
@Override
public void run () {
// your code here...
}
};
// schedule the task to run starting now and then every hour...
timer.schedule (hourlyTask, 0l, 1000*60*60);
如果您在 onPlayerInteract
函数中声明了 hourlyTask
,则您可以访问 l1
和 l2
.要进行编译,您需要将它们都标记为 final
.
If you declare hourlyTask
within your onPlayerInteract
function, then you can access l1
and l2
. To make that compile, you will need to mark both of them as final
.
使用 Timer
对象的好处是它可以处理多个 TimerTask
对象,每个对象都有自己的计时、延迟等.你也可以启动和停止只要你通过将 Timer
对象声明为类变量或其他东西来保持它的计时器.
The advantage of using a Timer
object is that it can handle multiple TimerTask
objects, each with their own timing, delay, etc. You can also start and stop the timers as long as you hold on to the Timer
object by declaring it as a class variable or something.
我不知道如何获得中间的每个块.
I don't know how to get every block in between.
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