查找失踪阵列数量 [英] Find missing numbers in array

问题描述

我试图找到类似以下的数组每个丢失号码。

I'm trying to find each missing number in an array like the following.

Array ( [0] => 1 [1] => 2 [2] => 3 [3] => 4 [4] => 5 [5] => 6 [6] => 7 [7] => 8 
[8] => 9 [9] => 10 [10] => 11 [11] => 12 [12] => 13 [13] => 14 [14] => 15 [15] => 16 
[16] => 17 [17] => 18 [18] => 19 [19] => 20 [20] => 21 [21] => 22 [22] => 23 
[23] => 24 [24] => 25 [25] => 26 [26] => 27 [27] => 28 [28] => 29 [29] => 30 
[30] => 31 [31] => 32 [32] => 33 [33] => 34 [34] => 35 [35] => 36 [36] => 37 
[37] => 38 [38] => 39 [39] => 40 [40] => 41 [41] => 42 [42] => 43 [43] => 44 
[44] => 45 [45] => 46 [46] => 47 [47] => 48 [48] => 49 [49] => 50 [50] => 51 
[51] => 52 [52] => 53 [53] => 54 [54] => 55 [55] => 56 [56] => 57 [57] => 58 
[58] => 59 [59] => 60 [60] => 61 [61] => 62 [62] => 63 [63] => 64 [64] => 67 
[65] => 68 [66] => 69 )

数字 65 ， 66 缺少这种特殊的阵列中的

The numbers 65,66 are missing in this particular array.

我的问题我怎么找出哪些号码与PHP的帮助失踪。具体是什么我需要找出是最低的失踪人数。

My question how do I figure out which numbers are missing with the help of PHP. Specifically what I need to find out is the lowest missing number.

为什么：因为当时我可以说一些分配给成员作为一个id

Why: Because then I can assign that number to a member as an id.

推荐答案

您可以使用和array_diff 和范围功能：

// given array. 3 and 6 are missing.
$arr1 = array(1,2,4,5,7); 

// construct a new array:1,2....max(given array).
$arr2 = range(1,max($arr1));                                                    

// use array_diff to get the missing elements 
$missing = array_diff($arr2,$arr1); // (3,6)

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