Scrapy:非阻塞暂停 [英] Scrapy: non-blocking pause
问题描述
我有问题.我需要停止一个函数的执行一段时间,但不能停止整体解析的实现.也就是说,我需要一个非阻塞的暂停.
I have a problem. I need to stop the execution of a function for a while, but not stop the implementation of parsing as a whole. That is, I need a non-blocking pause.
看起来像:
class ScrapySpider(Spider):
name = 'live_function'
def start_requests(self):
yield Request('some url', callback=self.non_stop_function)
def non_stop_function(self, response):
for url in ['url1', 'url2', 'url3', 'more urls']:
yield Request(url, callback=self.second_parse_function)
# Here I need some function for sleep only this function like time.sleep(10)
yield Request('some url', callback=self.non_stop_function) # Call itself
def second_parse_function(self, response):
pass
函数 non_stop_function 需要停止一段时间,但不应阻塞其余的输出.
Function non_stop_function needs to be stopped for a while, but it should not block the rest of the output.
如果我插入 time.sleep()
- 它会停止整个解析器,但我不需要它.是否可以使用 twisted
或其他方式停止一个函数?
If I insert time.sleep()
- it will stop the whole parser, but I don't need it. Is it possible to stop one function using twisted
or something else?
原因:我需要创建一个非阻塞函数,每 n 秒解析一次网站页面.在那里她会得到 urls 并填充 10 秒钟.获取到的网址会继续工作,但主要功能需要休眠.
Reason: I need to create a non-blocking function that will parse the page of the website every n seconds. There she will get urls and fill for 10 seconds. URLs that have been obtained will continue to work, but the main feature needs to sleep.
更新:
感谢 TkTech 和 viach.一个答案帮助我了解如何发出待处理的 Request
,第二个答案是如何激活它.两个答案相互补充,我为 Scrapy 做了一个很好的非阻塞暂停:
Thanks to TkTech and viach. One answer helped me to understand how to make a pending Request
, and the second is how to activate it. Both answers complement each other and I made an excellent non-blocking pause for Scrapy:
def call_after_pause(self, response):
d = Deferred()
reactor.callLater(10.0, d.callback, Request(
'https://example.com/',
callback=self.non_stop_function,
dont_filter=True))
return d
并根据我的请求使用此函数:
And use this function for my request:
yield Request('https://example.com/', callback=self.call_after_pause, dont_filter=True)
推荐答案
Request
对象具有 callback
参数,请尝试使用该参数.我的意思是,创建一个包含 self.second_parse_function
和 pause
的 Deferred
.
Request
object has callback
parameter, try to use that one for the purpose.
I mean, create a Deferred
which wraps self.second_parse_function
and pause
.
这是我的脏且未测试的示例,已标记更改的行.
Here is my dirty and not tested example, changed lines are marked.
class ScrapySpider(Spider):
name = 'live_function'
def start_requests(self):
yield Request('some url', callback=self.non_stop_function)
def non_stop_function(self, response):
parse_and_pause = Deferred() # changed
parse_and_pause.addCallback(self.second_parse_function) # changed
parse_and_pause.addCallback(pause, seconds=10) # changed
for url in ['url1', 'url2', 'url3', 'more urls']:
yield Request(url, callback=parse_and_pause) # changed
yield Request('some url', callback=self.non_stop_function) # Call itself
def second_parse_function(self, response):
pass
如果该方法适合您,那么您可以创建一个函数,该函数根据规则构造一个 Deferred
对象.它可以通过如下方式实现:
If the approach works for you then you can create a function which constructs a Deferred
object according to the rule. It could be implemented in the way like the following:
def get_perform_and_pause_deferred(seconds, fn, *args, **kwargs):
d = Deferred()
d.addCallback(fn, *args, **kwargs)
d.addCallback(pause, seconds=seconds)
return d
这里是可能的用法:
class ScrapySpider(Spider):
name = 'live_function'
def start_requests(self):
yield Request('some url', callback=self.non_stop_function)
def non_stop_function(self, response):
for url in ['url1', 'url2', 'url3', 'more urls']:
# changed
yield Request(url, callback=get_perform_and_pause_deferred(10, self.second_parse_function))
yield Request('some url', callback=self.non_stop_function) # Call itself
def second_parse_function(self, response):
pass
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