Scrapy:没有标题的 CSV 输出 [英] Scrapy: CSV output without header
问题描述
当我使用命令 scrapy crawl <project>-o <filename.csv>
,我得到带有标题的 Item
字典的输出.这很好.但是,如果文件已经存在,我希望scrapy 省略标题.scrapy 是否能够做到这一点,或者我是否需要实现该功能?
When I use the command scrapy crawl <project> -o <filename.csv>
, I get the output of my Item
dictionary with headers. This is good. However, I would like scrapy to omit headers if the file already exists. Is scrapy capable of doing this or do I need to implement that functionality?
推荐答案
CsvItemExporter
中有include_headers_line=True
但是不知道怎么直接用.http://doc.scrapy.org/en/latest/topics/exporters.html#csvitemexporter
There is include_headers_line=True
in CsvItemExporter
but I don't know how to use it directly. http://doc.scrapy.org/en/latest/topics/exporters.html#csvitemexporter
但是您可以使用 include_headers_line=False
在文件 exporters.py
(与 settings.py
和 代码>items.py
)
But you can create own exporter with include_headers_line=False
in file exporters.py
(in the same folder as settings.py
and items.py
)
from scrapy.exporters import CsvItemExporter
class HeadlessCsvItemExporter(CsvItemExporter):
def __init__(self, *args, **kwargs):
kwargs['include_headers_line'] = False
super(HeadlessCsvItemExporter, self).__init__(*args, **kwargs)
然后你必须在settings.py
FEED_EXPORTERS = {
'csv': 'your_project_name.exporters.HeadlessCsvItemExporter',
}
现在scrapy应该编写没有标题的csv文件.
And now scrapy should write csv file without headers.
scrapy crawl <project> -o <filename.csv>
或者你可以设置
FEED_EXPORTERS = {
'headless': 'your_project_name.exporters.HeadlessCsvItemExporter',
}
并且只有在您使用 -t headless
scrapy crawl <project> -o <filename.csv> -t headless
ps.不要忘记在 setttings.py
现在导出器仅在文件不为空时才跳过标题(如果 file.tell() > 0
)
Now exporter skips headers only if file is not empty (if file.tell() > 0
)
from scrapy.exporters import CsvItemExporter
class HeadlessCsvItemExporter(CsvItemExporter):
def __init__(self, *args, **kwargs):
# args[0] is (opened) file handler
# if file is not empty then skip headers
if args[0].tell() > 0:
kwargs['include_headers_line'] = False
super(HeadlessCsvItemExporter, self).__init__(*args, **kwargs)
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