通过结合使用scrapy在python中从图像中获取文本的基本网址? [英] by combining base url getting text out of image in python using scrapy?

问题描述

我试过这个代码:

src1 = "https://hms.harvard.edu/"<br/>
src = response.css('div.person-line > div > 
      img::attr("src")').extract_first()<br/>
src = sites/default/files/hms-faculty-emails/BX0UVXkP.jpg <br/>
import urlparse <br/>
urlparse.urljoin(src1, src)<br/>
https://hms.harvard.edu/sites/default/files/hms-faculty-emails/BX0UVXkP.jpg<br/>
src2 = urlparse.urljoin(src1,src)<br/>
email = pytesseract.image_to_string(Image.open(src2))<br/>

我收到此错误

ioerror errno 22 invalid mode ('rb') or filename

如何从文本图像中获取电子邮件文本..有人可以帮忙吗?

how to get email text out of text image..can any one help please?

推荐答案

你应该使用 io.BufferIO 缓冲区，因为你用 http<调用函数 image_to_string/代码> 路径.你需要写这样的代码:

You should use io.BufferIO buffer, because you call function image_to_string with http path. You need write code like this:

def get_text(src):
    response = urlopen(src)
    buffer = io.BytesIO(response.read())
    return pytesseract.image_to_string(Image.open(buffer))

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