用 IP 地址替换部分 URL [英] Replace part of URL with IP adress

问题描述

我想做的是下面的事情.我有一个网址，比如 http://www.google.com/one/two/three一个>

What I want to do is something like below. I have a URL, say http://www.google.com/one/two/three

我需要提取主域名www.google.com"，将其提供给 nslookup(因为 nslookup/dig 似乎不适用于完整 URL)，然后将 URL 替换为已解析的 IP 地址.例如

I need to extract the main domain name "www.google.com", to feed it to nslookup (As nslookup/dig does not seem to work with full URL) and then replace the URL with resolved IP address.e.g.

$ echo "http://www.google.com/one/two/three" | sed "s/<pattern>//g" 
$ www.google.com

问题是http://"可能并不总是存在.然后

The problem is that "http://" may not always be there. And then

$ echo "http://www.google.com/one/two/three" | sed "s/<pattern>//g" 
$ http://11.22.33.44/one/two/three

谁能提供任何相关链接或相关示例?

Can anyone provide any related link or related examples ?

推荐答案

试试这个 sed 命令:

Try this sed command:

echo "http://www.google.com/one/two/three" | sed -r 's#(https?://)?([^/]+).*#\2#'

输出:

www.google.com

当您获取 IP 地址时:

And when you have fetched IP address:

$> IP="11.22.33.44"
$> echo "https://www.google.com/one/two/three" | sed -r "s#(https?://)?([^/]+)(.*)#\1$IP\3#"
https://11.22.33.44/one/two/three

这将适用于 http://、https:// 或在 URL 前没有任何 https?://.

This will work with http://, https:// or without any https?:// before the URL.

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