使用 sed 仅打印每个段落的第一个单词 [英] Print only the first word of each paragraph using sed

问题描述

我想知道如何使用 sed one-liner 仅打印出每个段落的第一个单词.在这种情况下，段落由跟随 2 个换行符的文本定义.

I am wondering how I can print out only the first word of every paragraph with a sed one-liner. A paragraph in this case is defined by a text that follows 2 line breaks.

例如

This is a paragraph with some text. Some random text that is not really important.

This is another paragraph with some text.
However this sentence is still in the same paragraph.

这个应该改成

This

This

推荐答案

一个可能的 GNU sed 解决方案是:

A possible GNU sed solution would be:

sed -rn ':a;/^ *$/{n;ba};s/( |$).*//p;:b;n;/^ *$/ba;bb'

输出:

This
This

它将仅有空格的行视为空行，并理解段落之间的任意数量的空行.也能正确处理一个单词的段落.

It treats spaces-only lines as empty and understands any number of empty lines between paragraphs. Also processes one-word paragraphs correctly.

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