如何 sed 具有特定模式的文本块? [英] How to sed a block of text with specific pattern?

问题描述

我有这样的文件

...
%pythons
Albino
Black Bee
Bumble Bee
%end

%boa
Albino
Jungle
Pastel
%end
...

为了保存或替换目的，我想从这个文件匹配模式中 sed 整个块.块中的行数可能非常多.我需要通用的解决方案.我正在寻找这样的东西

I would like to sed one whole block from this file matching pattern for saving or sustitution purposes.Number of lines in a block may very. I need common solution. I'm looking for something like this

sed -n '/^%boa(**something here**)^%end$//p' snakes > boa
sed 's/^%boa(**something here**)^%end$/(**new block**)/' snakes > snakes_updated

我正在专门寻找 sed 解决方案.任何带有解释的建议将不胜感激.

I'm looking specifically for sed solution. Any suggestions with explanation would be very appreciated.

推荐答案

这可能对你有用(GNU sed):

This might work for you (GNU sed):

sed -i -e '/%boa/,/%end/{w fileb' -e '/%end/!d;r filec' -e 'd}' filea

这会将 %boa 和 %end 之间的部分写入 fileb 并将其替换为 filec 的内容.使用 -i 标志将 filea 的内容替换为已编辑的操作.

This writes the section between %boa and %end to fileb and replaces it with the contents of filec. The contents of filea is replaced by the edited operations by using the -i flag.

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