sed 中的正则表达式用于搜索和替换(无效参考) [英] regex in sed for search & replace (invalid reference)

问题描述

我想用 shell 和正则表达式替换一行中的字符串.

I would like to replace a string in a line with shell and regex.

例如，在文件 configuration.php 中，我想将 TO_REPLACE 替换为 OK_REPLACE:

For example, in file configuration.php I would like to replace TO_REPLACE with OK_REPLACED:

public $user = 'TO_REPLACE';

我试过这个命令:

cd ~/public_html; sed -i "s/^\public $user = *'[^']*'/\1OK_REPLACED'/g" configuration.php

但我收到此错误

sed: -e expression #1, char 39: invalid reference \1 on `s' command's RHS

我也试过这个，但没有

sed -i "s/^\(public \$user = *')[^']*'/\1OK_REPLACED'/g" configuration.php

推荐答案

我认为你的括号必须是平衡的.您的第一个带有反斜杠前缀，但第二个不是.试试这个:

I think your parenthesis must be balanced. Your first one is prefixed with a backslash, but the 2nd one is not. Try this:

sed -i "s/^\(public \$user = *'\)[^']*'/\1OK_REPLACED'/g" configuration.php

或者这个:

sed -r -i "s/^(public \$user = *')[^']*'/\1OK_REPLACED'/g" configuration.php

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