Sequelize:Include.where 按“父"模型属性过滤 [英] Sequelize: Include.where filtering by a 'parent' Model attribute
问题描述
我有两个相关的模型,目录和产品类别.后者有一个组合 PK,'id,language_id'.以下是简化的模型:
I have two Models related, Catalog and ProductCategory. The latter has a composed PK, 'id, language_id'. Here are the models simplified:
var Catalog = sequelize.define("Catalog", {
id: {
type: DataTypes.INTEGER,
primaryKey: true,
autoIncrement: true
},
user_id: {
type: DataTypes.INTEGER,
allowNull: false
},
product_category_id: {
type: DataTypes.STRING(7)
},
language_id: {
type: DataTypes.INTEGER
},
... more stuff ...
}
var ProductCategory = sequelize.define("ProductCategory", {
id: {
type: DataTypes.STRING(7),
primaryKey: true
},
language_id: {
type: DataTypes.INTEGER,
primaryKey: true
},
... more stuff ...
}
Catalog.belongsTo(models.ProductCategory, {foreignKey: 'product_category_id'});
我试图从 ProductCategory 表中包含一些与 Catalog 相关的信息,但仅当 language_id 匹配时才包含.
I'm trying to include some info from ProductCategory table related to Catalog, but ONLY when the language_id matches.
目前我正在从两个表中获取所有可能的匹配项.这是现在的查询:
At the moment I'm getting all the possible matches from both tables. This is the query right now:
Catalog.find({where:
{id: itemId},
include: {
model: models.ProductCategory,
where: {language_id: /* Catalog.language_id */}
}
})
有没有办法使用 Catalog 中的属性来过滤两个模型具有相同语言的包含?
Is there a way to use an attribute from Catalog to filter the include where both models have the same language?
顺便说一句,我也尝试过更改 where 子句,没有任何后果:
By the way, I've also tried changing the where clause, without any consecuence:
where: {'ProductCategory.language_id': 'Catalog.language_id'}
推荐答案
Sequelize 为这种情况提供了一个额外的运算符 $col
所以你不必使用 sequelize.literal('...')
(这更像是一个黑客).
Sequelize provides an extra operator $col
for this case so you don't have to use sequelize.literal('...')
(which is more a hack).
在您的示例中,用法如下所示:
In your example the usage would look like this:
Catalog.find({where:
{id: itemId},
include: {
model: models.ProductCategory,
where: {
language_id: {$col: 'Catalog.language_id'}
}
}
})
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