“#!/bin/sh"行是什么意思?在 UNIX shell 脚本中是什么意思? [英] What does the line "#!/bin/sh" mean in a UNIX shell script?

问题描述

我正在阅读一些 shell 脚本教程，并找到了以下示例程序:

I was going through some shell script tutorials and found the following sample program:

#!/bin/sh
clear
echo "HELLO WORLD"

谁能告诉我开头的注释 #!/bin/sh 的意义是什么?

Can anyone please tell me what the significance of the comment #!/bin/sh at the start is?

推荐答案

它被称为 shebang，它告诉父 shell 应该使用哪个解释器来执行脚本.

It's called a shebang, and tells the parent shell which interpreter should be used to execute the script.

#!/bin/sh <--------- bourne shell compatible script
#!/usr/bin/perl  <-- perl script
#!/usr/bin/php  <--- php script
#!/bin/false <------ do-nothing script, because false returns immediately anyways.

大多数脚本语言倾向于将以#开头的行解释为注释，并且会忽略下面的!/usr/bin/whatever 部分，否则可能会导致解释语言中的语法错误.

Most scripting languages tend to interpret a line starting with # as comment and will ignore the following !/usr/bin/whatever portion, which might otherwise cause a syntax error in the interpreted language.

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