仅适用于扩展初始化列表 [英] extended initializer lists only available with

问题描述

我很新的C ++和我无法读我的错误，我能够消除大部分人，但我到了几个，我对他们要求帮助，请。

下面是节目

 的#include＆LT;串GT;
＃包括LT＆;＆iostream的GT;
使用命名空间std;
诠释主（）{
 为int * bN的新= INT [9];
 串BANKNUM;
 为int *数= INT新[9];
 INT总，依然存在;
 为int *多= INT新{7,3,9,7,3,9,7,3};
 COUT＆所述;＆下;请输入位于支票底部银行号码＆下;其中p ENDL;
 CIN＆GT;＆GT; BANKNUM;
 的for（int i = 0; I＆LT; 8;我++）{
  bN的[I] =（BANKNUM [I] -48）;
 }
 的for（int i = 0; I＆LT; 8;我++）{
  COUT＆LT;＆LT; bN的[I]
 }
 COUT＆LT;＆LT; ENDL;
 的for（int i = 0; I＆LT; 8;我++）{
  COUT＆LT;＆LT;多[我]
 }
 COUT＆LT;＆LT; ENDL;
 的for（int i = 0; I＆LT; 8;我++）{
  bN的[I] = bN的[I] *多[我]
  COUT＆LT;＆LT; bN的[I]
 }
 COUT＆LT;＆LT; ENDL;
 的for（int i = 0; I＆LT; 8;我++）{
  总+ = bN的[I]
  COUT＆LT;＆LT;全;
 }
 COUT＆LT;＆LT; ENDL;
 保持=总％10;
 如果（保持==（BANKNUM [9]  -  48））{
  COUT＆LT;＆LT;的个数为valad＆LT;＆LT; ENDL;
  COUT＆LT;＆LT;保持＆LT;＆LT; ENDL;
 }
}
 

和错误

  wm018 @ CS：〜$ C ++ bankNum.cpp
bankNum.cpp：在功能上是不是主要的（）A：
bankNum.cpp：9：19：警告：扩展初始化列表仅适用于-std = C ++ 0x或-std = GNU ++ 0x中[默认启用]
bankNum.cpp：9：38：错误：无法A＆LT转换，大括号内的初始化列表＆gt;将在初始化âintâ
bankNum.cpp：30：3：错误：预期;④âcoutâ前
 

解决方案

初始化的这种风格，使用大括号：

 为int *多= INT新{7,3,9,7,3,9,7,3};
 

被介绍给在2011年较早的编译器不支持它的语言;一些较新的（像你这样）只支持它，如果你告诉他们;你的编译器：

  C ++ -std =的C ++ 0x bankNum.cpp
 

不过，这种形式的初始化仍然无效与创建数组新的。由于它的小，只在本地使用，你可以声明本地阵列;这并不需要C ++ 11的支持：

  INT多[] = {7,3,9,7,3,9,7,3};
 

这也有固定的内存泄漏的优势 - 如果你使用新来分配内存，那么你应该用释放它删除当你完成它。

如果您确实需要动态分配，你应该使用的std ::矢量来分配和释放内存为您提供：

 的std ::矢量＆lt;＆INT GT;多{7,3,9,7,3,9,7,3};
 

要注意的是你的GCC的版本是很老了，对C ++ 11不完全的支持。

I'm very new to C++ and I'm having trouble reading my errors I was able to eliminate most of them but I'm down to a few and I'm request help on them please.

Here is the program

#include <string>
#include <iostream>
using namespace std;
int main(){
 int *bN = new int[9];
 string bankNum;
 int *number = new int[9];
 int total, remain;
 int *multi = new int{7,3,9,7,3,9,7,3};
 cout<<"Please enter the bank number located at the bottom of the check"<<endl;
 cin>>bankNum;
 for(int i = 0; i < 8; i++){
  bN[i]= (bankNum[i]-48);
 }
 for(int i = 0; i < 8;i++){
  cout<<bN[i];
 }
 cout<<endl;
 for(int i = 0; i < 8;i++){
  cout<<multi[i];
 }
 cout<<endl;
 for(int i = 0; i < 8;i++){
  bN[i] = bN[i] * multi[i];
  cout<< bN[i];
 }
 cout<<endl;
 for(int i = 0; i < 8;i++){
  total += bN[i]
  cout<<total;
 }
 cout<<endl;
 remain = total % 10;
 if(remain == (bankNum[9] - 48)){
  cout<<"The Number is valad"<<endl;
  cout<<remain<<endl;
 }
}

and the errors

wm018@cs:~$ c++ bankNum.cpp
bankNum.cpp: In function âint main()â:
bankNum.cpp:9:19: warning: extended initializer lists only available with -std=c++0x or -std=gnu++0x [enabled by default]
bankNum.cpp:9:38: error: cannot convert â<brace-enclosed initializer list>â to âintâ in initialization
bankNum.cpp:30:3: error: expected â;â before âcoutâ

解决方案

This style of initialisation, using braces:

int *multi = new int{7,3,9,7,3,9,7,3};

was introduced to the language in 2011. Older compilers don't support it; some newer ones (like yours) only support it if you tell them; for your compiler:

c++ -std=c++0x bankNum.cpp

However, this form of initialisation still isn't valid for arrays created with new. Since it's small and only used locally, you could declare a local array; this doesn't need C++11 support:

int multi[] = {7,3,9,7,3,9,7,3};

This also has the advantage of fixing the memory leak - if you use new to allocate memory, then you should free it with delete when you've finished with it.

If you did need dynamic allocation, you should use std::vector to allocate and free the memory for you:

std::vector<int> multi {7,3,9,7,3,9,7,3};

Beware that your version of GCC is quite old, and has incomplete support for C++11.

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