R- sqldf 错误原始与双精度 [英] R- sqldf error raw vs double

查看:27
本文介绍了R- sqldf 错误原始与双精度的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个向量 lims,有分数的限制:

 [1] 0.000000 7.025894 9.871630 12.411131 15.155998 18.099176 21.431354 25.391163 30.6165550 6 3

我创建了一个表格来对其他客户进行分类:

lims[1]<- -0.00001a<-data.frame(lims[2:10])colnames(a)<-'maxSc'a<-rbind(a, 100)lims<-data.frame(lims)lims$maxSc<-acolnames(lims)<-c('minSc', 'maxSc')>班级(lims)[1]数据框"

所以我的结果是:

<代码>>利姆斯最小Sc 最大Sc1 -0.000010 7.0258942 7.025894 9.8716303 9.871630 12.4111314 12.411131 15.1559985 15.155998 18.0991766 18.099176 21.4313547 21.431354 25.3911638 25.391163 30.6165509 30.616550 40.35663010 40.356630 100.000000

我想根据这些限制和字段 sc 对另一个表(火车)进行分类:

>class(train$sc)[1]数字">班级(火车$目标)[1] 整数"

但是当我运行以下命令时,出现错误:

库(sqldf)sqldf("选择b.minSc, b.maxSc, count(*) 作为total, sum(target) as compra从火车 a 左加入 lims b在 a.sc<=b.maxSc 和 a.sc>b.minSc分组 b.minSc, b.maxSc")

<块引用>

sqliteSendQuery(conn, statement, bind.data) 中的错误:RAW() 可以仅适用于原始",而不适用于双重"

我不明白我做错了什么.

解决方案

我相信错误在于您的 lims 对象.

lims <- c(0.000000, 7.025894, 9.871630, 12.411131,15.155998、18.099176、21.431354、25.391163、30.616550、40.356630)lims[1]<--0.00001a<-data.frame(lims[2:10])colnames(a)<-'maxSc'a<-rbind(a, 100)lims<-data.frame(lims)lims$maxSc<-acolnames(lims)<-c('minSc', 'maxSc')sapply(lims,类)# minSc maxSc# "数字" "data.frame"

注意 lims$maxScdata.frame 类型.然后以下查询不起作用并导致您发布的错误.

库(sqldf)sqldf("从 lims 中选择 *")

但是,如果将 lims$maxSc 设置为 a[,1] 则没有错误.

lims$maxSc<-a[,1]sapply(lims,class)# minSc maxSc# "数字" "数字"sqldf("从 lims 中选择 *")

data.frame 的列不能是 data.frame 类,以便 sqldf 可以工作.

I have a vector lims, with the limits of a score:

 [1]  0.000000  7.025894  9.871630 12.411131 15.155998 18.099176 21.431354 25.391163 30.616550 40.356630

I create a table to classify other clients with:

lims[1]<- -0.00001 
a<-data.frame(lims[2:10])
colnames(a)<-'maxSc'
a<-rbind(a, 100)
lims<-data.frame(lims)
lims$maxSc<-a
colnames(lims)<-c('minSc', 'maxSc')


> class(lims)
[1] "data.frame"

So my result is:

> lims
       minSc      maxSc
1  -0.000010   7.025894
2   7.025894   9.871630
3   9.871630  12.411131
4  12.411131  15.155998
5  15.155998  18.099176
6  18.099176  21.431354
7  21.431354  25.391163
8  25.391163  30.616550
9  30.616550  40.356630
10 40.356630 100.000000

I want to classify another table (train) according to those limits and the field sc:

>class(train$sc)
[1] "numeric"
> class(train$target)
[1] "integer"

But when I run the following I get an error:

library(sqldf)
sqldf("Select b.minSc, b.maxSc, count(*) as total, sum(target) as compra
     from  train a left join lims b 
    on a.sc<=b.maxSc and a.sc>b.minSc
    group by b.minSc, b.maxSc")

Error in sqliteSendQuery(conn, statement, bind.data) : RAW() can only be applied to a 'raw', not a 'double'

I don't understand what I'm doing wrong.

解决方案

I believe the error lies in your lims object.

lims <- c(0.000000,  7.025894,  9.871630, 12.411131, 
          15.155998, 18.099176, 21.431354, 25.391163, 
          30.616550, 40.356630)

lims[1]<- -0.00001 
a<-data.frame(lims[2:10])
colnames(a)<-'maxSc'
a<-rbind(a, 100) 
lims<-data.frame(lims)
lims$maxSc<-a
colnames(lims)<-c('minSc', 'maxSc')
sapply(lims, class)

#     minSc        maxSc 
# "numeric" "data.frame" 

Notice that lims$maxSc is of type data.frame. Then the following query doesn't work and results in the error you posted.

library(sqldf)
sqldf("select * from lims")

However, if instead lims$maxSc is set to a[,1] then there is no error.

lims$maxSc<-a[,1]
sapply(lims,class)
#     minSc     maxSc 
# "numeric" "numeric" 
sqldf("select * from lims")

The columns of your data.frame cannot be of class data.frame for sqldf to work.

这篇关于R- sqldf 错误原始与双精度的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆