iPhone 中的 sqlite 中的“数据库已锁定" [英] 'database is locked' in sqlite in iPhone

问题描述

朋友你好，我已经搜索了很多关于这个错误的信息.我发现了一些建议，比如你必须使用 sqlite_finalize() 语句，我使用它.看看我的代码.

Hello friends I have searched a lot about this error. I found some advice like you must use sqlite_finalize() statement and I use it. Have a look on my code.

-(void) updatePostingsForLike:(NSString *)postingKey isLiked:(NSString *)isLiked{

-(void) updatePostingsForLike:(NSString *)postingKey isLiked:(NSString *)isLiked{

  [self initWithDB]; 
  sqlite3_stmt *stmt;

  if(sqlite3_open([[self dbPath] UTF8String],&(db)) == SQLITE_OK) {

      NSString *str=[@"" stringByAppendingFormat:@"update posting set isLiked='%@' where postKey='%@'",isLiked,postingKey];
      const char *sql=[str cStringUsingEncoding:NSUTF8StringEncoding];
      int status;
      status= sqlite3_prepare_v2(db,sql, -1, &stmt, NULL);

      if(SQLITE_DONE != sqlite3_step(stmt))
      {
          NSLog(@"%s",sqlite3_errmsg(db));

      }

      sqlite3_finalize(stmt);

      [self closeConnection];

  }}

我遵守了所有规则.我只能更新我的记录一次.仅限第一次.它第二次抛出错误.解决方案应该是什么?自从过去 2 天以来，我一直在遇到这样的问题！

I followed all the rules. I can update my record only once. First time only. It throws error on second time. What should be the solution ? I stuck in such problem since last 2 days !

推荐答案

试试这个，

-(void) updatePostingsForLike:(NSString *)postingKey isLiked:(NSString *)isLiked
{

   [self initWithDB]; 
   sqlite3_stmt *statement;

   if(sqlite3_open([[self dbPath] UTF8String],&db) == SQLITE_OK)
   {
      NSString* query=[NSString stringWithFormat: @"update posting set isLiked='%@' where   postKey='%@'",isLiked,postingKey];
      const char *query_stmt = [query UTF8String];

     if (sqlite3_prepare_v2(db, query_stmt, -1, &statement, NULL) == SQLITE_OK)
     {
        while (sqlite3_step(statement) == SQLITE_ROW)
        { 
            sqlite3_column_text(statement, 0);
        } 
        sqlite3_finalize(statement);
     }
    sqlite3_close(db);
  }
}

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