在PHP阵列的复制总和 [英] sum of duplicates in array php
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问题描述
林不知道的关于这个搜索功能是什么这么不能似乎帮助自己。似乎是一个明显的问题真的。
我有一个数组,并在那里我有重复键,我想补充的值。例如:
这是我的数组的一个部分。
[1] =>排列
(
[inputAvg] => 21.41 KB
[outputAvg] => 22.03 KB
[日期] => 2011-08-01
)[2] =>排列
(
[inputAvg] => 182.63 KB
[outputAvg] => 186.05 KB
[日期] => 2011-08-01
)[3] =>排列
(
[inputAvg] => 182.63 KB
[outputAvg] => 186.05 KB
[日期] => 2011-08-02
)[4] =>排列
(
[inputAvg] => 4.84 MB
[outputAvg] => 4.93 MB
[日期] => 2011-08-03
)
我只想做的是,说其中数组之日起关键是相同的(如这里2011-08-01)我要一次显示这个日期,但有重复的项目组合值.... ?
例如
[1] =>排列
(
[inputAvg] => 204.04 KB
[outputAvg] => 208.08 KB
[日期] => 2011-08-01
)
[2] =>排列
(
[inputAvg] => 182.63 KB
[outputAvg] => 186.05 KB
[日期] => 2011-08-02
)[3] =>排列
(
[inputAvg] => 4.84 MB
[outputAvg] => 4.93 MB
[日期] => 2011-08-03
)
解决方案
< PHP$阵列=阵列(阵列(inputAvg=> 21.41,outputAvg=> 22.03,日期=>中2011-08-01),
阵列(inputAvg=> 182.63,outputAvg=> 186.05,日期=>中2011-08-01),
阵列(inputAvg=> 182.63,outputAvg=> 186.05,日期=>中2011-08-02)
);$解析度=阵列();
的foreach($数组作为$瓦尔斯){
如果(array_key_exists($瓦尔斯['日期'],$水库)){
$水库[$瓦尔斯['日期'] ['inputAvg'] + = $瓦尔斯['inputAvg'];
$水库[$瓦尔斯['日期'] ['outputAvg'] + = $瓦尔斯['outputAvg'];
$水库[$瓦尔斯['日期'] ['日期'] = $瓦尔斯['日期'];
}
其他{
$水库[$瓦尔斯['日期'] = $丘壑;
}
}回声< pre>中;
的print_r($水库);?>
输出:
阵列
(
[2011-08-01] =>排列
(
[inputAvg] => 204.04
[outputAvg] => 208.08
[日期] => 2011-08-01
) [2011-08-02] =>排列
(
[inputAvg] => 182.63
[outputAvg] => 186.05
[日期] => 2011-08-02
))
Im not sure what function to search for in regards to this so cant seem to help myself. Seems like an obvious problem really. I have an array, and where I have duplicate keys, I wish to add the values. e.g:
This is a section of my array.
[1] => Array
(
[inputAvg] => 21.41 KB
[outputAvg] => 22.03 KB
[date] => 2011-08-01
)
[2] => Array
(
[inputAvg] => 182.63 KB
[outputAvg] => 186.05 KB
[date] => 2011-08-01
)
[3] => Array
(
[inputAvg] => 182.63 KB
[outputAvg] => 186.05 KB
[date] => 2011-08-02
)
[4] => Array
(
[inputAvg] => 4.84 MB
[outputAvg] => 4.93 MB
[date] => 2011-08-03
)
All I wish to do is, say where the date key of the array is the same (e.g. here 2011-08-01) I want to show this date once, but with combined values of the duplicate item....?
e.g
[1] => Array
(
[inputAvg] => 204.04 KB
[outputAvg] => 208.08 KB
[date] => 2011-08-01
)
[2] => Array
(
[inputAvg] => 182.63 KB
[outputAvg] => 186.05 KB
[date] => 2011-08-02
)
[3] => Array
(
[inputAvg] => 4.84 MB
[outputAvg] => 4.93 MB
[date] => 2011-08-03
)
解决方案
<?php
$array = array(Array("inputAvg" => 21.41,"outputAvg" => 22.03,"date" => "2011-08-01"),
Array("inputAvg" => 182.63,"outputAvg" => 186.05,"date" => "2011-08-01" ),
Array("inputAvg" => 182.63, "outputAvg" => 186.05,"date" => "2011-08-02")
);
$res = array();
foreach($array as $vals){
if(array_key_exists($vals['date'],$res)){
$res[$vals['date']]['inputAvg'] += $vals['inputAvg'];
$res[$vals['date']]['outputAvg'] += $vals['outputAvg'];
$res[$vals['date']]['date'] = $vals['date'];
}
else{
$res[$vals['date']] = $vals;
}
}
echo "<pre>";
print_r($res);
?>
Output :
Array
(
[2011-08-01] => Array
(
[inputAvg] => 204.04
[outputAvg] => 208.08
[date] => 2011-08-01
)
[2011-08-02] => Array
(
[inputAvg] => 182.63
[outputAvg] => 186.05
[date] => 2011-08-02
)
)
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