CSV到C中的数组 [英] CSV into array in C

问题描述

我试图加载一个CSV文件到一个单一的维数组。我可以输出CSV文件的内容，而是在尝试将它复制到我有一点麻烦的数组。

I'm trying to load a CSV file into a single dimentional array. I can output the contents of the CSV file, but in trying to copy it into an array I'm having a bit of trouble.

下面是我现有的code，我意识到可能是pretty坏，但我自学：

Here is my existing code, which I realise is probably pretty bad but I'm teaching myself:

#include <stdio.h>
#include <string.h>

#define MAX_LINE_LENGTH 1024
#define MAX_CSV_ELEMENTS 1000000

int main(int argc, char *argv[])
{
    char line[MAX_LINE_LENGTH] = {0};
    int varCount = 0;
    char CSVArray[MAX_CSV_ELEMENTS] = {0};

    FILE *csvFile = fopen("data.csv", "r");

    if (csvFile)
    {
        char *token = 0;
        while (fgets(line, MAX_LINE_LENGTH, csvFile)) 
        {
            token = strtok(&line[0], ",");
            while (token)
            {
                varCount++;
                CSVArray[varCount] = *token; //This is where it all goes wrong
                token = strtok(NULL, ",");
            }
        }
        fclose(csvFile);
    }
    return 0;
}

有没有更好的办法，我应该这样做呢？在此先感谢！

Is there a better way I should be doing this? Thanks in advance!

推荐答案

*标记表示取消引用指针标记这是 strtok的找到的第一个字符的字符串的地址。这就是为什么你的code填充 CSVArray 只有每个记号的第一个字符。

*token means dereferencing the pointer token which is the address of the first character in a string that strtok found. That's why your code fills CSVArray with just the first characters of each token.

您应该宁愿字符指针数组的标记点，如：

You should rather have an array of char pointers to point at the tokens, like:

char *CSVArray[MAX_CSV_ELEMENTS] = {NULL};

然后指针分配给它的元素：

And then assign a pointer to its elements:

CSVArray[varCount] = token;

另外，你可以在每次复制整个令牌：

Alternatively, you can copy the whole token each time:

CVSArray[varCount] = malloc(strlen(token)+1);
strcpy(CVSArray[varCount], token);

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